Depth system in pixi?

[Josepho]

Hi there, is there any kind of way to z sort the displayobjects in an easy way in pixi?

 

Has the displayobjects any kind of atribute that zsorts them in the renderer or anything like that? or should i sort them in the child array by myself?

 

Thanks!

[Sebi]

The children array is rendered from top to bottom, so you have to sort that array on your own.

Afaik theres no z-order system yet, but should be fairly easy to overwrite the addChild method to support z-index.

[1-800-STAR-WARS]

There's also an addChildAt method which will let you insert a display object in the middle of the list.

[Mat Groves]

Yo! Assuming you have a z property on you sprites to control depth..

function depthCompare(a, {  if (a.z < b.z)     return -1;  if (a.z > b.z)    return 1;  return 0;}myContainer.children.sort(depthCompare);

[Josepho]

Many thanks!

[vitolipari]

Hi to everybody.
I have two containers, how can i sort all object into the two system?

I have a particle system ( a PIXI.SpriteBatch ) and some sprite into the stage.

Every spriteBatch object and every stage sprite have the "z" attribute.
I would sort the sprite ( into the stage ) and the objects ( into the sproteBatch ) based on the "z" attribute.

[neonwarge04]

With all due respect. I don't know why z-index is not part of PIXI. C'mon, even SFML has this. What's your excuse on this one? 

[ivan.popelyshev]

There can be 100 different implementations of Z-layer, we can do them as a plugins. Just tell me what kind of z-index you need, do you want to use DEPTH_BUFFER or sort all sprites in scene?

 

 

C'mon, even SFML has this. What's your excuse on this one? 

 

For example, that thing will mess with filters and particles.

[xerver]

With all due respect. I don't know why z-index is not part of PIXI. C'mon, even SFML has this. What's your excuse on this one?

SFML is also not a 2d library, it is a gl wrapper.

PIXI is not a gl wrapper, it is a 2D library.

Z-index in 2D games is very application specific. We left that to userland.