JackFalcon

Performance Optimization tips.

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Question about setEnabled(false). Is it better performance than visibility = 0 ?

And wondering what is the difference?

If 1 mesh is rotating 10 children, and 5 can be hidden - which is more performant: visibility or setEnabled(false);

I'll test it....

Lots of reading. 

Thanks!  

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Statistics -->great idea<--

Thank you setEnabled(true) insight!

TINY-UPDATES: 

- the code below worked well as first pass rough-in.

RESULTS: performance improvement achieved! (ding).

- Will try setEnabled... on parents

-  -> But had interesting PROBLEM: need parent setEnabled(true) AND children setEnabled(false)???<--

       anyway... : )

- Hello LOD! too.

- Probably date.now all three [hope] (BZ thx).


reloadLevel = function(){
    for(var i=0; i<edges.length; i++){ edges[i].visibility = 1; }
    for(var i=0; i<orbs.length; i++){ orbs[i].visibility = 1; }
    for(var i=0; i<boxes.length; i++){ boxes[i].visibility = 1; }
    for (var i=0; i<tiles.length; i++){ tiles[i].visibility = 1; }
}

unloadLevel = function(){
    for(var i=0; i<edges.length; i++){ edges[i].visibility = 0; }
    for(var i=0; i<orbs.length; i++){ orbs[i].visibility = 0; }
    for(var i=0; i<boxes.length; i++){ boxes[i].visibility = 0; }
    for (var i=0; i<tiles.length; i++){ tiles[i].visibility = 0; }
}

 

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Ok,

Put in TIMESTAMPS ... gotta go.

Thanks to who'ever made dude.

Here is adapted timestamp utility, to easily measure performance anywhere:

//TIMER
var timeStamp = 0;
var currentTimeStamp = 0;
var timeReport = function(testname){
    console.log('TIMESTART: '+testname);
    if(!timeStamp){ timeStamp = new Date().getTime(); }
    return function (testname) {
        currentTimeStamp = new Date().getTime();
        var timeDelta = currentTimeStamp - timeStamp;
        console.log('TIMESTOP: '+testname+' = '+timeDelta);
        timeStamp = null;
    }
}
//EXAMPLE-USAGE-.
// var debugTimeStop = timeReport('START Time Test');
// debugTimeStop('END Time Test');

Statistics pending...

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rudimentary stats... 

TEST DESCRIPTION: rotating parent with gradual increasing number of children(30,60,90) for each rotation, step-interpolation = 0.02, on a closed-circuit track.

BASELINE   NO-PERF-OPS   3 CONTROL-TESTS:

TIMESTART: START-ANIMATION
TIMESTOP: END-ORBIT = 1867
TIMESTART: START-ANIMATION
TIMESTOP: END-ORBIT = 4294
TIMESTART: START-ANIMATION
TIMESTOP: END-ORBIT = 6724

 

OP-TEST-1  visibility = 0    3 COMPARISON-TESTS:

TIMESTART: START-ANIMATION
TIMESTOP: END-ORBIT = 1937
TIMESTOP: END-ORBIT = 4237
TIMESTOP: END-ORBIT = 4679

OP-TEST-1 RESULTS:

Within variance, visibility = 0 for hidden mesh, reduces orbit time ~2 seconds on third rotation (HOO-RAY).

QUESTION: which is better visibility or setEnabled(false)?

Bird should read source code, or...

TEST: replace vis =0 to  setEnable(false) in the same loops...

TIMESTART: START-ANIMATION
TIMESTOP: END-ORBIT = 1917
TIMESTOP: END-ORBIT = 4227
TIMESTOP: END-ORBIT = 4778
 

RESULTS:

Interesting - visibility is slightly faster (within variance). 

Didn't expect that. Bird should read source code.

NOTE: couldn't use setElement(false) at parent level because in context need parent to remain visible, and only children hidden.

NEXT-STEPS: 

Not going to do LOD test, sticking with simple visibility op for the moment.

Instances not applicable.

This is solved. Maybe more PERFOPS later.

Hope this helps someone.

 

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