oschakravarthi

Roof facing facet.

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Hi all,

I have a simple requirement but i have no clue how to  do it.

I have a mesh (may look like box).

1. I need to identify its top/roof facing facet(s).

2. Devide this plane into cells (like each cell is a 5*5 in size) and get the coordinates of these cells.

Please help me.

Thanks in advance.

 

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1. for each facet look at the direction of normal in world space (compute dot of face normal and vector up or down for instance).

2. I do not understand the question or goal (seems similar to what facet partitioning is doing)

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Thank you @JohnK

I now understood how the information is stored internally. The below function get the details.

var getFacetTrianglesOfMesh = function (mesh) {
            var indices = mesh.getIndices();
            var positions = mesh.getVerticesData(BABYLON.VertexBuffer.PositionKind);

            var nbFaces = indices.length / 3;

            var triangles = [];
            for (var i = 0; i < nbFaces; i++) {
                var triangle = [];
                for (var j = 0; j < 3; j++) {
                    var ind = (i * 3) + j;
                    var point = new BABYLON.Vector3(positions[ind], positions[ind + 1], positions[ind + 2]);
                    triangle.push(point);
                }

                triangles.push(triangle);
            }

            return triangle;
        };

Now I need to do face sampling. I need to divide each facet into a grid of equal sized cells. 

Any clue how to do this? Gone thru this article but could not understand. https://chrischoy.github.io/research/barycentric-coordinate-for-mesh-sampling/

 

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