Xav

Vertices Position on cube

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a cube has 6 sides

each side is composed with 2 triangular facets, so 4 vertices.

Side vertices aren't shared with other sides so they can hold different UVs and normals per side.

I total : 4 * 6 = 24 vertices... some are in the same location.

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thank you Jerome

I'm ok with you all 24 vertices match with  nbrVertices = cube.getTotalVertices ();

I follow you well on the 6 face with 4 vertices per face.
There are then 6 vertices of each face that have the same coordinates.

What I would like to do is group them ... :huh: like this

exemple.jpg

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Create an array with vertices that are the same coordinated in the same index
for example
myCubeVertices = [[all vertices with same coordinates xyz], [all vertices with same coordinates xyz], ...] ?
Does this seem to me easier to visualize and manipulate?

 

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27 minutes ago, Xav said:

Create an array with vertices that are the same coordinated in the same index
for example
myCubeVertices = [[all vertices with same coordinates xyz], [all vertices with same coordinates xyz], ...] ?
Does this seem to me easier to visualize and manipulate?

 

Hi @Xav

Group Vertices

https://playground.babylonjs.com/#3CZLNK#1 

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I continued my research and I also found this post which helps to understand the function:

On the other side I haven't found information to adapt the uv according to the new position of vertices?

var uvs = mesh.getVerticesData(BABYLON.VertexBuffer.UVKind);

mesh.setVerticesData(BABYLON.VertexBuffer.UVKind, uvs);

What is the relationship between a vertex position vector3 and a UV position vector2 ? :unsure:

Thanks

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