Bitmapdata at x and y position

[proyb2]

How is bmd2 can be move to x and y position?

var createBox = game.make.bitmapData(100,6)createBox.fill(0,0,0,1)createBox.addToWorld() //At 0,0var bmd2 = game.make.bitmapData(1,1)var rect = new Phaser.Rectangle(0,0,1,1)bmd2.copyRect(createBox.canvas,rect)//orbmd2.copy(createBox.canvas,100,100,20,100) //Don't seem to able to move to x:100px and y:100px position?

 

[rich]

If you look at the method signature for copy you'll see the first few parameters are where to copy from (not to).

 

For this example specifically I'd just do:

var bmd2 = game.make.bitmapData(1,1)var rect = new Phaser.Rectangle(0,0,1,1)bmd2.copyRect(createBox.canvas,rect, 100, 100)

[proyb2]

I see and the position is still at 0,0 despite change with the code below.

bmd2.copyRect(createBox.canvas,rect, 100, 100)

[rich]

Position of what? bmd2 within createBox, or createBox in the world?

[proyb2]

To set the position of x and y bmd2 in game world.

[rich]

But bmd2 hasn't been added to the game world. It's just a 1x1 bitmapData. If you want it to appear in the game world then it needs adding:

bmd2.addToWorld(100, 100);

[proyb2]

Maybe you may try on JSFiddle? I think there is a bug that bmd2 isn't showing after bmd2.addToWorld

[rich]

You create one, I'll review it. As far as I can see from the above you've a 1x1 transparent pixel somewhere on screen. Good luck finding it

[vspinnet]

On the topic, I have my bitmap data added to my world as you've shown:

bmd2.addToWorld(100, 100);

But, now I need to reposition my bitmap data within my world. How do I change the x/y position after it's been added to the world?

[vspinnet]

I noticed 

move(x, y, wrap)

I assumed that the method moved the bitmap the amount of x and y relative to the bitmap's current location, but I'm going to give this a try and see if it works relative to the top left of the world.

 

EDIT

Quote

The amount of pixels to horizontally shift the canvas by. Use a negative value to shift to the left, positive to the right.

This seems to indicate that the x and y are relative to the current location..

[rich]

Look at the docs, specifically look at what BitmapData.addToWorld() returns. That should tell you all you need to know!

[vspinnet]

3 hours ago, rich said:

Look at the docs, specifically look at what BitmapData.addToWorld() returns. That should tell you all you need to know!

Thanks.