Creation of a Vector3 that is a certain distance from another Vector3

[mCard]

I need to create a Vector3 that is a certain distance away from another Vector3, which is on a line. Basically, I am trying to create a tube that ends in the middle of a cone to create an arrow. However, I already changed the pivot matrix to be the point of the cone and the cone has already been aligned along an axis between two spheres. Is there an easy way to find a Vector3 to serve as the tube's endpoint in Babylon or do I have to solve all of the calculus by hand. So far, the closest I've gotten is a calculus equation. 

I know two Vector3 that are on the line, and the distance that the third Vector3 must be from the second Vector3.

[GameMonetize]

Hello you may need something along these lines:

// Pseudo code

var dist = vec2.subtract(vec1);

dist.normalize();

dist.scaleInPlace(10);// the distance you want from vec2

var vec3 = vec2.add(dist);