D&Q Mining is a high-tech company integrating R&D, production and sales. It provides mature products and solutions such as crushers, sand making, milling equipment, mobile crushing stations, etc., for aggregate, mining and waste recycling.

The connectable line of Swellex rock bolts, Pm24C, is a true alternative as long secondary support to secure potentially unstable areas or to control dilution while boosting productivity. The Swellex Premium line also comes in a plasticoated version for corrosion protection.

MoreGeneral information Swellex Pm12 Minimum breaking load 110 kN Minimum yielding load 90 kN Minimum elongation 10% Expansion pressure 300 bar For further information, see also technical data page 7. Minimum elongation "A": According to EN-ISO 6892-1 where applicable. Swellex Pm12 rock bolts Size Length (m) Weight (kg)

More7 Swellex rock bolts Swellex load capacity Description Minimum breaking load, expanded profile (kN) Minimum yielding load, expanded profile (kN) Minimum elongation "A5" (%) Profile diameter (mm) Material thickness (mm) Original tube diameter (mm) Injection bushing diameter (mm) Bushing head (mm) Bore hole diameter (mm) Expansion pressure (bar) Pm12 110 90 10 28 2 41 28 30/37 32-39 300

MoreA Tensile Force Of 80 KN Is Loaded As Shown. Although The Shear Stress Induced On The Pin Is Significant, It Is Also Subjected To Crushing Stress. Estimate The Shearing Stress On The 25-mm Diameter Pin And The Crushing Stress Between The 70 Mm Thick Bar And The Pin. X Y 80 KN B 80 KN

MoreType Swellex rock bolts Type Swellex anchoring tube acts or transfers its load by friction, It applies mainly to the reinforcement and improving internal friction strata or wall structures in mining excavation and as a roof reinforcement mainly in the construction of tunnels.

More6 The Atlas Copco MAI SDA is a unique bolting solution for unstable ground conditions such as sand, gravel, silt, and clays, and in soft to medium fractured rock formations. For

MoreAt the attachment points at the top of each truss structure, the peak tensile force is around 80 kN, which is below the 100 kN capacity of the connection. Keep in mind that a negative reaction force in the 1-direction means that the member is being pulled away from the wall. The lower attachments are in compression (positive reaction force

Moreaxial tensile force of 50 KN. The rods are co-axial and a small amount of angular movement between their axes is permissible. Design the joint and specify the dimensions of its components. Select suitable materials for the parts [4]. ANS: Given, P=50 KN= 50 :10 7 N I. Selection of material The rods are subjected to tensile force.

MoreJun 06, 2012· EX:9 A 400 mm long bar has rectangular cross-section 10 mm × 30 mm. This bar is subjected to(i) 15 kN tensile force on 10 mm × 30 mm faces,(ii) 80 kN compressive force on 10 mm × 400 mm faces, and(iii) 180 kN tensile force on 30 mm × 400 mm faces.Find the change in volume if E = 2 × 105 N/mm2 and μ = 0.3. 43 44.

MoreAt the attachment points at the top of each truss structure, the peak tensile force is around 80 kN, which is below the 100 kN capacity of the connection. Keep in mind that a negative reaction force in the 1-direction means that the member is being pulled away from the wall. The lower attachments are in compression (positive reaction force

Morefrom (2a) max. tensile force Fz = –4,09 kN and from (2b) max. compression force Fz = 12,10 kN (2a) Fz,min ≥ Fv (2b) Fz,max ≤ B · 1 – Fv B · Mb 2 · Mb,max Mb 2 · Mb,max When the equations (2a) and (2b) are resolved according to Fv, the minimum pretension force required or the maximum permissible pretension force can be

MoreAB carries a 7.5-kN force. If the link has a 14 ×4-mm rectangular cross section, calculate the tensile stress within it. Approach: Calculate the tensile stress σ = F/A with F = 7.5 kN = 7500 N and assume the cross sectional area of link AB is constant. Solution: Cross–sectional area: A = (14 mm) (4 mm) = 56 mm2 = 56 × 10–6 m2 Tensile stress:

Moreaxial tensile force of 50 KN. The rods are co-axial and a small amount of angular movement between their axes is permissible. Design the joint and specify the dimensions of its components. Select suitable materials for the parts [4]. ANS: Given, P=50 KN= 50 :10 7 N I. Selection of material The rods are subjected to tensile force.

Moreforce of 1 kN is shown in fig. The shaft is made of plain carbon steel 45C8 and the tensile yield strength is 380 N/mm2. The factor of safety is 2. Determine the

MoreJun 06, 2012· EX:9 A 400 mm long bar has rectangular cross-section 10 mm × 30 mm. This bar is subjected to(i) 15 kN tensile force on 10 mm × 30 mm faces,(ii) 80 kN compressive force on 10 mm × 400 mm faces, and(iii) 180 kN tensile force on 30 mm × 400 mm faces.Find the change in volume if E = 2 × 105 N/mm2 and μ = 0.3. 43 44.

MoreAug 01, 2014· The tensile strength of the twin-strand cable tested is 380 kN. According to Fig. 13a, its frictional strength is R = 170 kN/0.95 m = 179 kN/m and the critical embedment length thus (380/179) = 2.1 m. Both the inflatable bolt and the twin strand cable slipped because their embedment lengths (both 0.95 m) were shorter than their critical

More4) A joint is subjected to a tensile force 200 kN. Assuming Single-V groove weld joint and the throat thickness of 6 mm, find the effective length of weld? (Site welding) b. c. d. 100 mm 200 mm 300 mm 250 mm No, the answer is incorrect. Score: 0 Accepted Answers: 5) A pipe of 80 mm dia and 6 mm thick is connected to a 12 mm thick plate.

MoreJun 11, 2013· Problem 1.5-8 A steel bar of length 2.5 m with asquare cross section 100 mm on each side is subjectedto an axial tensile force of 1300 kN (see figure). Assumethat E ϭ 200 GPa and v ϭ 0.3.Determine the increase in volume of the bar.24 CHAPTER 1 Tension, Compression, and Shear100 mm100 mm1300 kN2.5 m1300 kNSolution 1.5-8 Square bar in

MoreWhat is the force required to accelerate an object with a mass of 20 kg from stationary to 3 m/s 2? F = m * a. F = 20 kg * 3 m/s 2. F = 60 N. Newtons are a derived unit, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one

MoreMay 23, 2018· P1.2 A circular pipe with outside diameter of 4.5 in. and wall thickness of 0.375 in. is subjected to an axial tensile force of 42,000 lb. Compute the average normal stress in the pipe

MoreShear force is 75 kN Tensile force is 12 kN also I am applying some moments to the bolt that is 15 kN-m. I have only one shear plane available I just want to know how this moment is distributed in the bolt as I am applying this perpendicular to the shear plane of the bolt.

MoreDesigned for full-amplitude tensile and compression fatigue testing, these grips offer superior ease-of-operation and ensure high-accuracy testing for a wide range of tests. Maximum test force ±20 to 200 kN

MoreThrust is a reaction force described quantitatively by Newton's third law.When a system expels or accelerates mass in one direction, the accelerated mass will cause a force of equal magnitude but opposite direction, to be applied to that system. The force applied on a surface in a direction perpendicular or normal to the surface is also called thrust. Force, and thus thrust, is measured

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