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Found 3 results

  1. Hello, I have searched a solution for a problem for long time and didn't found, if someone have some ideas I am taking all x) did someone know if it's possible to rotate a group of bodies around an anchor point, I set some bodies for invisble walls and my objective is to turn them around by 90° around an anchor point, I know It must be not very comprehensive so I set up an Image to explain myself. In the screen, I have 2 bodies and I want them to turn around the red dot what must be my anchor point, I know it's impossible in arcade so I tried in P2 physics and impossible to found any solution :/ Thanks for reading, feel free to leave a feedback
  2. [SOLVED] AI movement question

    Alright, been stuck on this for a few days and starting to think I'm overlooking a very simple solution. I have a character that I want to walk back and forth on the screen. He needs to walk to one edge, turn around, then walk to the other edge, again turn, walk, etc.; rinse and repeat. I've tried simply '+=' and '-=' on his x coord with an if statement but he wont seem to walk in the other direction. Example, writing 'steve.x += 1;' then 'steve.x -= 1;' won't work. He gets to one edge but then stops. I've also tried using tweens but he seems to become jittery as he's a spritesheet already, maybe? His physics body will stay, but the pixels themselves seem to move outOfBounds. Anyway, here's the full code for what I'm working on, any help is greatly appreciated. http://pastebin.com/V0GM7z3w Also still learning Phaser so any feedback on code flow is helpful too! Thanks!
  3. Hello developers, I want to ask you a question ( it could be silly but I can't find anything that works in the forum or other articles ). I want to rotate one line around a circle and I will attach an image to understand me perfectly what i mean. So i searched a lot about rotation of sprites with Phaser but I can't find a working example or a working function that will do what I want. I'm pretty sure my thing is not a big deal so it should be available to be done. I hope you can help me, Nick.